| Description |
|---|
| At the top | Hole no. | Distance from end in cm | Time for 10 oscillations | Time period in sec | Mean time period, T (sec) |
|---|---|---|---|---|---|
| 1 | 10 | ||||
| E | |||||
| N | 2 | 20 | |||
| D | |||||
| A | 3 | 30 | |||
| 4 | 40 | ||||
| 1 | 60 | ||||
| E | |||||
| N | 2 | 70 | |||
| D | |||||
| B | 3 | 80 | |||
| 4 | 90 | ||||
| Calculation from grpah |
|---|
|
Length: AC = C - A cm BD = B - D cm Mean Length: L = (AC + BD) / 2 cm |
|
Corresponding time period from the graph: T = from graph g' = 4π² L / T² ms-2 (100 cm = 1 m) |
|
Error: E = | g - g' ⁄ g | x 100% |
| Gravity = ms-2 Error = & |
| Point | Explanation |
|---|---|
| 1 | The comppund pendulum ws suspended from a rigid support. |
| 2 | The pendulum was slightly displaced from it's equilibrium position to start oscillation. |
| 3 | Small angular displacements were ensured so tht the motion approximates simple harmonic motion. |
| 4 | Time for 10 oscillations were taken from both ends with 8 holes with difference of 10 cm between each. |
| 5 | The time period and mean period were calculated. |
| 6 | A graph was drawn, distances in x-axis(10 small box = 10 cm) and mean time period in y-axis(first 10 = 1.5 afer 0.1 increase for 10 boxes) in table-I. |
| 7 | A line drawn that cuts between both lines twice with precise marks(T), and add points A,B,C and D. Now substract between CA and DB, then find mean length(L). |
| 8 | Find g' with formula 4𝜋2 ( L ⁄ T2 ) |
| 9 | Calculate the error. |
| 10 | Errors occured due to air resistance, small errors in timing or imperfect alignment. Results were noted down. |